Base | Representation |
---|---|
bin | 1110110110110101111… |
… | …1100000011000110111 |
3 | 220101211010011210002001 |
4 | 3231231133200120313 |
5 | 13140212422434020 |
6 | 313131120000131 |
7 | 24304041411124 |
oct | 3555537403067 |
9 | 811733153061 |
10 | 255240046135 |
11 | 99279396498 |
12 | 41573460047 |
13 | 1b0b88865c9 |
14 | c4d471b74b |
15 | 698cd8a50a |
hex | 3b6d7e0637 |
255240046135 has 16 divisors (see below), whose sum is σ = 306645120000. Its totient is φ = 203954145696.
The previous prime is 255240046133. The next prime is 255240046147. The reversal of 255240046135 is 531640042552.
It is a cyclic number.
It is not a de Polignac number, because 255240046135 - 21 = 255240046133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255240046094 and 255240046103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255240046133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16654006 + ... + 16669324.
It is an arithmetic number, because the mean of its divisors is an integer number (19165320000).
Almost surely, 2255240046135 is an apocalyptic number.
255240046135 is a deficient number, since it is larger than the sum of its proper divisors (51405073865).
255240046135 is a wasteful number, since it uses less digits than its factorization.
255240046135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18990.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 255240046135 its reverse (531640042552), we get a palindrome (786880088687).
The spelling of 255240046135 in words is "two hundred fifty-five billion, two hundred forty million, forty-six thousand, one hundred thirty-five".
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