Base | Representation |
---|---|
bin | 100101001001111101111… |
… | …010011101010101011111 |
3 | 100001002120110210011220210 |
4 | 211021331322131111133 |
5 | 313313201200102320 |
6 | 5232551434143503 |
7 | 352320503554521 |
oct | 45117572352537 |
9 | 10032513704823 |
10 | 2553323050335 |
11 | 8a494932a222 |
12 | 352a26881b93 |
13 | 156a14a44b25 |
14 | 8b81d89da11 |
15 | 466400ad0e0 |
hex | 2527de9d55f |
2553323050335 has 8 divisors (see below), whose sum is σ = 4085316880560. Its totient is φ = 1361772293504.
The previous prime is 2553323050259. The next prime is 2553323050349. The reversal of 2553323050335 is 5330503233552.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2553323050335 - 226 = 2553255941471 is a prime.
It is a super-2 number, since 2×25533230503352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2553323050293 and 2553323050302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85110768330 + ... + 85110768359.
It is an arithmetic number, because the mean of its divisors is an integer number (510664610070).
Almost surely, 22553323050335 is an apocalyptic number.
2553323050335 is a deficient number, since it is larger than the sum of its proper divisors (1531993830225).
2553323050335 is a wasteful number, since it uses less digits than its factorization.
2553323050335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170221536697.
The product of its (nonzero) digits is 607500, while the sum is 39.
Adding to 2553323050335 its reverse (5330503233552), we get a palindrome (7883826283887).
The spelling of 2553323050335 in words is "two trillion, five hundred fifty-three billion, three hundred twenty-three million, fifty thousand, three hundred thirty-five".
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