2553333140261 has 2 divisors, whose sum is σ = 2553333140262. Its totient is φ = 2553333140260.

The previous prime is 2553333140233. The next prime is 2553333140263. The reversal of 2553333140261 is 1620413333552.

2553333140261 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2128710180100 + 424622960161 = 1459010^2 + 651631^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553333140261 - 2¹⁰ = 2553333139237 is a prime.

Together with 2553333140263, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2553333140263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276666570130 + 1276666570131.

It is an arithmetic number, because the mean of its divisors is an integer number (1276666570131).

Almost surely, 2^{2553333140261} is an apocalyptic number.

It is an amenable number.

2553333140261 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553333140261 is an equidigital number, since it uses as much as digits as its factorization.

2553333140261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 38.

The spelling of 2553333140261 in words is "two trillion, five hundred fifty-three billion, three hundred thirty-three million, one hundred forty thousand, two hundred sixty-one".