Base | Representation |
---|---|
bin | 1110110111001111110… |
… | …0111001000110000011 |
3 | 220102002200002101012100 |
4 | 3231303330321012003 |
5 | 13140423143202203 |
6 | 313145550401443 |
7 | 24306525461001 |
oct | 3556374710603 |
9 | 812080071170 |
10 | 255348412803 |
11 | 99324581a20 |
12 | 415a3800283 |
13 | 1b1051693b3 |
14 | c504c89a71 |
15 | 6997643ea3 |
hex | 3b73f39183 |
255348412803 has 24 divisors (see below), whose sum is σ = 404452030320. Its totient is φ = 153954754560.
The previous prime is 255348412757. The next prime is 255348412811. The reversal of 255348412803 is 308214843552.
255348412803 is a `hidden beast` number, since 2 + 553 + 4 + 8 + 4 + 12 + 80 + 3 = 666.
It is not a de Polignac number, because 255348412803 - 210 = 255348411779 is a prime.
It is a super-2 number, since 2×2553484128032 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (255348412103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6662958 + ... + 6701171.
It is an arithmetic number, because the mean of its divisors is an integer number (16852167930).
Almost surely, 2255348412803 is an apocalyptic number.
255348412803 is a deficient number, since it is larger than the sum of its proper divisors (149103617517).
255348412803 is a wasteful number, since it uses less digits than its factorization.
255348412803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13364339 (or 13364336 counting only the distinct ones).
The product of its (nonzero) digits is 921600, while the sum is 45.
The spelling of 255348412803 in words is "two hundred fifty-five billion, three hundred forty-eight million, four hundred twelve thousand, eight hundred three".
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