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255348412803 = 321119313364129
BaseRepresentation
bin1110110111001111110…
…0111001000110000011
3220102002200002101012100
43231303330321012003
513140423143202203
6313145550401443
724306525461001
oct3556374710603
9812080071170
10255348412803
1199324581a20
12415a3800283
131b1051693b3
14c504c89a71
156997643ea3
hex3b73f39183

255348412803 has 24 divisors (see below), whose sum is σ = 404452030320. Its totient is φ = 153954754560.

The previous prime is 255348412757. The next prime is 255348412811. The reversal of 255348412803 is 308214843552.

255348412803 is a `hidden beast` number, since 2 + 553 + 4 + 8 + 4 + 12 + 80 + 3 = 666.

It is not a de Polignac number, because 255348412803 - 210 = 255348411779 is a prime.

It is a super-2 number, since 2×2553484128032 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (255348412103) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6662958 + ... + 6701171.

It is an arithmetic number, because the mean of its divisors is an integer number (16852167930).

Almost surely, 2255348412803 is an apocalyptic number.

255348412803 is a deficient number, since it is larger than the sum of its proper divisors (149103617517).

255348412803 is a wasteful number, since it uses less digits than its factorization.

255348412803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13364339 (or 13364336 counting only the distinct ones).

The product of its (nonzero) digits is 921600, while the sum is 45.

The spelling of 255348412803 in words is "two hundred fifty-five billion, three hundred forty-eight million, four hundred twelve thousand, eight hundred three".

Divisors: 1 3 9 11 33 99 193 579 1737 2123 6369 19107 13364129 40092387 120277161 147005419 441016257 1323048771 2579276897 7737830691 23213492073 28372045867 85116137601 255348412803