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2553541433 is a prime number
BaseRepresentation
bin1001100000110011…
…1111001100111001
320120221221100022122
42120030333030321
520212201311213
61101215131025
7120164513132
oct23014771471
96527840278
102553541433
1110a0453523
125b3213a75
13319057781
141a31cac89
15ee2a4d08
hex9833f339

2553541433 has 2 divisors, whose sum is σ = 2553541434. Its totient is φ = 2553541432.

The previous prime is 2553541373. The next prime is 2553541451. The reversal of 2553541433 is 3341453552.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2521244944 + 32296489 = 50212^2 + 5683^2 .

It is a cyclic number.

It is not a de Polignac number, because 2553541433 - 226 = 2486432569 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2553541393 and 2553541402.

It is not a weakly prime, because it can be changed into another prime (2553547433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276770716 + 1276770717.

It is an arithmetic number, because the mean of its divisors is an integer number (1276770717).

Almost surely, 22553541433 is an apocalyptic number.

It is an amenable number.

2553541433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553541433 is an equidigital number, since it uses as much as digits as its factorization.

2553541433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108000, while the sum is 35.

The square root of 2553541433 is about 50532.5779374059. The cubic root of 2553541433 is about 1366.8293724655.

Adding to 2553541433 its reverse (3341453552), we get a palindrome (5894994985).

The spelling of 2553541433 in words is "two billion, five hundred fifty-three million, five hundred forty-one thousand, four hundred thirty-three".