Base | Representation |
---|---|
bin | 10111110010010011… |
… | …011010110010010111 |
3 | 2102220221001002200002 |
4 | 113302103122302113 |
5 | 404301220410312 |
6 | 15422151041515 |
7 | 1562622346622 |
oct | 276223326227 |
9 | 72827032602 |
10 | 25540013207 |
11 | a916742a35 |
12 | 4b4937029b |
13 | 254038b167 |
14 | 1343d96db9 |
15 | 9e72e14c2 |
hex | 5f24dac97 |
25540013207 has 2 divisors, whose sum is σ = 25540013208. Its totient is φ = 25540013206.
The previous prime is 25540013153. The next prime is 25540013251. The reversal of 25540013207 is 70231004552.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25540013207 - 26 = 25540013143 is a prime.
It is a super-2 number, since 2×255400132072 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 25540013207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25540013267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12770006603 + 12770006604.
It is an arithmetic number, because the mean of its divisors is an integer number (12770006604).
Almost surely, 225540013207 is an apocalyptic number.
25540013207 is a deficient number, since it is larger than the sum of its proper divisors (1).
25540013207 is an equidigital number, since it uses as much as digits as its factorization.
25540013207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 29.
Adding to 25540013207 its reverse (70231004552), we get a palindrome (95771017759).
The spelling of 25540013207 in words is "twenty-five billion, five hundred forty million, thirteen thousand, two hundred seven".
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