Base | Representation |
---|---|
bin | 111010000101001001010101… |
… | …010000010110011111101001 |
3 | 1020111102212002202211212111212 |
4 | 322011021111100112133221 |
5 | 231440113231204441410 |
6 | 2303135354424402505 |
7 | 104542645066145150 |
oct | 7205112520263751 |
9 | 1214385082755455 |
10 | 255440315312105 |
11 | 744336a1750a50 |
12 | 24796064916435 |
13 | ac6bbc28961c1 |
14 | 471153d182597 |
15 | 1e7e8c7336b05 |
hex | e852554167e9 |
255440315312105 has 32 divisors (see below), whose sum is σ = 382175711723520. Its totient is φ = 159231162582720.
The previous prime is 255440315312099. The next prime is 255440315312107. The reversal of 255440315312105 is 501213513044552.
It is not a de Polignac number, because 255440315312105 - 220 = 255440314263529 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (255440315312107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5031476 + ... + 23155914.
It is an arithmetic number, because the mean of its divisors is an integer number (11942990991360).
Almost surely, 2255440315312105 is an apocalyptic number.
It is an amenable number.
255440315312105 is a deficient number, since it is larger than the sum of its proper divisors (126735396411415).
255440315312105 is a wasteful number, since it uses less digits than its factorization.
255440315312105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18161069.
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 255440315312105 its reverse (501213513044552), we get a palindrome (756653828356657).
The spelling of 255440315312105 in words is "two hundred fifty-five trillion, four hundred forty billion, three hundred fifteen million, three hundred twelve thousand, one hundred five".
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