Base | Representation |
---|---|
bin | 100101001011101001010… |
… | …110110101001010110111 |
3 | 100001021020002200201221011 |
4 | 211023221112311022313 |
5 | 313330344131300403 |
6 | 5233450350133051 |
7 | 352413252450445 |
oct | 45135126651267 |
9 | 10037202621834 |
10 | 2555125650103 |
11 | 8a56938aa0a4 |
12 | 35324a4b1187 |
13 | 156c41335300 |
14 | 8b951051b95 |
15 | 466e847ba6d |
hex | 252e95b52b7 |
2555125650103 has 24 divisors (see below), whose sum is σ = 2774437380000. Its totient is φ = 2352066223104.
The previous prime is 2555125650083. The next prime is 2555125650109. The reversal of 2555125650103 is 3010565215552.
It is not a de Polignac number, because 2555125650103 - 217 = 2555125519031 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2555125650109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 179312523 + ... + 179326771.
It is an arithmetic number, because the mean of its divisors is an integer number (115601557500).
Almost surely, 22555125650103 is an apocalyptic number.
2555125650103 is a deficient number, since it is larger than the sum of its proper divisors (219311729897).
2555125650103 is a wasteful number, since it uses less digits than its factorization.
2555125650103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17131 (or 17118 counting only the distinct ones).
The product of its (nonzero) digits is 225000, while the sum is 40.
The spelling of 2555125650103 in words is "two trillion, five hundred fifty-five billion, one hundred twenty-five million, six hundred fifty thousand, one hundred three".
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