Base | Representation |
---|---|
bin | 1011100111111011110101… |
… | …10110111110111101111100 |
3 | 10100111122110201120111102121 |
4 | 11303331322312332331330 |
5 | 11322244232333100130 |
6 | 130210430025532324 |
7 | 5245515415530526 |
oct | 563757266767574 |
9 | 110448421514377 |
10 | 25561411612540 |
11 | 816559651a491 |
12 | 2a49b810440a4 |
13 | 113557a53922b |
14 | 645270d72a16 |
15 | 2e4d9e828d7a |
hex | 173f7adbef7c |
25561411612540 has 12 divisors (see below), whose sum is σ = 53678964386376. Its totient is φ = 10224564645008.
The previous prime is 25561411612523. The next prime is 25561411612543. The reversal of 25561411612540 is 4521611416552.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25561411612543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 639035290294 + ... + 639035290333.
It is an arithmetic number, because the mean of its divisors is an integer number (4473247032198).
Almost surely, 225561411612540 is an apocalyptic number.
25561411612540 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
25561411612540 is an abundant number, since it is smaller than the sum of its proper divisors (28117552773836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
25561411612540 is a wasteful number, since it uses less digits than its factorization.
25561411612540 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1278070580636 (or 1278070580634 counting only the distinct ones).
The product of its (nonzero) digits is 288000, while the sum is 43.
The spelling of 25561411612540 in words is "twenty-five trillion, five hundred sixty-one billion, four hundred eleven million, six hundred twelve thousand, five hundred forty".
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