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2557066453 is a prime number
BaseRepresentation
bin1001100001101001…
…1011110011010101
320121012120102201221
42120122123303111
520214102111303
61101422450341
7120236464144
oct23032336325
96535512657
102557066453
1110a2440967
125b44339b1
133199c0096
141a386775b
15ee74e4bd
hex9869bcd5

2557066453 has 2 divisors, whose sum is σ = 2557066454. Its totient is φ = 2557066452.

The previous prime is 2557066433. The next prime is 2557066483. The reversal of 2557066453 is 3546607552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2511813924 + 45252529 = 50118^2 + 6727^2 .

It is a cyclic number.

It is not a de Polignac number, because 2557066453 - 225 = 2523512021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2557066433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278533226 + 1278533227.

It is an arithmetic number, because the mean of its divisors is an integer number (1278533227).

Almost surely, 22557066453 is an apocalyptic number.

It is an amenable number.

2557066453 is a deficient number, since it is larger than the sum of its proper divisors (1).

2557066453 is an equidigital number, since it uses as much as digits as its factorization.

2557066453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756000, while the sum is 43.

The square root of 2557066453 is about 50567.4445963013. Note that the first 3 decimals coincide. The cubic root of 2557066453 is about 1367.4580269127.

The spelling of 2557066453 in words is "two billion, five hundred fifty-seven million, sixty-six thousand, four hundred fifty-three".