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255766500151 = 733503650687
BaseRepresentation
bin1110111000110011011…
…1110001001100110111
3220110011210210102012221
43232030313301030313
513142302211001101
6313255243423211
724323063244361
oct3561467611467
9813153712187
10255766500151
1199519581158
124169b824b07
131b170971666
14c5445dbd31
1569be1cbaa1
hex3b8cdf1337

255766500151 has 4 divisors (see below), whose sum is σ = 259270150912. Its totient is φ = 252262849392.

The previous prime is 255766500139. The next prime is 255766500169. The reversal of 255766500151 is 151005667552.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 255766500151 - 225 = 255732945719 is a prime.

It is a super-3 number, since 3×2557665001513 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 255766500098 and 255766500107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (255766510151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1751825271 + ... + 1751825416.

It is an arithmetic number, because the mean of its divisors is an integer number (64817537728).

Almost surely, 2255766500151 is an apocalyptic number.

255766500151 is a deficient number, since it is larger than the sum of its proper divisors (3503650761).

255766500151 is an equidigital number, since it uses as much as digits as its factorization.

255766500151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3503650760.

The product of its (nonzero) digits is 315000, while the sum is 43.

The spelling of 255766500151 in words is "two hundred fifty-five billion, seven hundred sixty-six million, five hundred thousand, one hundred fifty-one".

Divisors: 1 73 3503650687 255766500151