Base | Representation |
---|---|
bin | 1011101001000101101011… |
… | …10011011111111001011101 |
3 | 10100122102210120002110111020 |
4 | 11310202311303133321131 |
5 | 11323421430121312003 |
6 | 130240543514514353 |
7 | 5251421005136424 |
oct | 564426563377135 |
9 | 110572716073436 |
10 | 25601055260253 |
11 | 818038a304800 |
12 | 2a557a57359b9 |
13 | 1139227820145 |
14 | 64715209c2bb |
15 | 2e5e1edbed53 |
hex | 1748b5cdfe5d |
25601055260253 has 24 divisors (see below), whose sum is σ = 37523008035744. Its totient is φ = 15514548735840.
The previous prime is 25601055260251. The next prime is 25601055260257. The reversal of 25601055260253 is 35206255010652.
It is not a de Polignac number, because 25601055260253 - 21 = 25601055260251 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25601055260251) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1726450 + ... + 7360892.
It is an arithmetic number, because the mean of its divisors is an integer number (1563458668156).
Almost surely, 225601055260253 is an apocalyptic number.
It is an amenable number.
25601055260253 is a deficient number, since it is larger than the sum of its proper divisors (11921952775491).
25601055260253 is a wasteful number, since it uses less digits than its factorization.
25601055260253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5646985 (or 5646974 counting only the distinct ones).
The product of its (nonzero) digits is 540000, while the sum is 42.
The spelling of 25601055260253 in words is "twenty-five trillion, six hundred one billion, fifty-five million, two hundred sixty thousand, two hundred fifty-three".
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