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2560601321041 is a prime number
BaseRepresentation
bin100101010000101111101…
…110110110111001010001
3100001210100201010122100111
4211100233232312321101
5313423102414233131
65240153552521321
7352666042052611
oct45205756667121
910053321118314
102560601321041
118a7a43766785
12354318250241
131576048ab29a
148bd10374a41
1546919042ab1
hex2542fbb6e51

2560601321041 has 2 divisors, whose sum is σ = 2560601321042. Its totient is φ = 2560601321040.

The previous prime is 2560601320999. The next prime is 2560601321081. The reversal of 2560601321041 is 1401231060652.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1572954930625 + 987646390416 = 1254175^2 + 993804^2 .

It is a cyclic number.

It is not a de Polignac number, because 2560601321041 - 223 = 2560592932433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2560601320994 and 2560601321012.

It is not a weakly prime, because it can be changed into another prime (2560601321081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280300660520 + 1280300660521.

It is an arithmetic number, because the mean of its divisors is an integer number (1280300660521).

Almost surely, 22560601321041 is an apocalyptic number.

It is an amenable number.

2560601321041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2560601321041 is an equidigital number, since it uses as much as digits as its factorization.

2560601321041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 2560601321041 its reverse (1401231060652), we get a palindrome (3961832381693).

The spelling of 2560601321041 in words is "two trillion, five hundred sixty billion, six hundred one million, three hundred twenty-one thousand, forty-one".