Base | Representation |
---|---|
bin | 11110100010010… |
… | …00110010100101 |
3 | 122211222210200201 |
4 | 33101020302211 |
5 | 1011033310233 |
6 | 41230110501 |
7 | 6230150011 |
oct | 1721106245 |
9 | 584883621 |
10 | 256150693 |
11 | 121654897 |
12 | 7194b431 |
13 | 410b7176 |
14 | 2603b541 |
15 | 1774b77d |
hex | f448ca5 |
256150693 has 2 divisors, whose sum is σ = 256150694. Its totient is φ = 256150692.
The previous prime is 256150607. The next prime is 256150703. The reversal of 256150693 is 396051652.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 254945089 + 1205604 = 15967^2 + 1098^2 .
It is a cyclic number.
It is not a de Polignac number, because 256150693 - 213 = 256142501 is a prime.
It is a super-2 number, since 2×2561506932 = 131226355048760498, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (256150603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128075346 + 128075347.
It is an arithmetic number, because the mean of its divisors is an integer number (128075347).
Almost surely, 2256150693 is an apocalyptic number.
It is an amenable number.
256150693 is a deficient number, since it is larger than the sum of its proper divisors (1).
256150693 is an equidigital number, since it uses as much as digits as its factorization.
256150693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48600, while the sum is 37.
The square root of 256150693 is about 16004.7084634491. The cubic root of 256150693 is about 635.0849850089.
The spelling of 256150693 in words is "two hundred fifty-six million, one hundred fifty thousand, six hundred ninety-three".
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