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2561551180413 = 3853850393471
BaseRepresentation
bin100101010001101000010…
…110010010001001111101
3100001212210220110111110020
4211101220112102021331
5313432024100233123
65240432123402353
7353031424532121
oct45215026221175
910055726414406
102561551180413
118a8390953125
123545423833b9
13157726611054
148bda058d581
154697261c7e3
hex2546859227d

2561551180413 has 4 divisors (see below), whose sum is σ = 3415401573888. Its totient is φ = 1707700786940.

The previous prime is 2561551180403. The next prime is 2561551180427. The reversal of 2561551180413 is 3140811551652.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2561551180413 - 240 = 1462039552637 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2561551180403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426925196733 + ... + 426925196738.

It is an arithmetic number, because the mean of its divisors is an integer number (853850393472).

Almost surely, 22561551180413 is an apocalyptic number.

It is an amenable number.

2561551180413 is a deficient number, since it is larger than the sum of its proper divisors (853850393475).

2561551180413 is an equidigital number, since it uses as much as digits as its factorization.

2561551180413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 853850393474.

The product of its (nonzero) digits is 144000, while the sum is 42.

The spelling of 2561551180413 in words is "two trillion, five hundred sixty-one billion, five hundred fifty-one million, one hundred eighty thousand, four hundred thirteen".

Divisors: 1 3 853850393471 2561551180413