Base | Representation |
---|---|
bin | 111010001111101001000110… |
… | …001011001010110000001011 |
3 | 1020120222210220111212000022202 |
4 | 322033221012023022300023 |
5 | 232033422442400111104 |
6 | 2304451004442510415 |
7 | 104646031443506204 |
oct | 7217510613126013 |
9 | 1216883814760282 |
10 | 256161616800779 |
11 | 74691593623338 |
12 | 24891a0720540b |
13 | acc1c242474c1 |
14 | 473840755a5ab |
15 | 1e9354154151e |
hex | e8fa462cac0b |
256161616800779 has 2 divisors, whose sum is σ = 256161616800780. Its totient is φ = 256161616800778.
The previous prime is 256161616800751. The next prime is 256161616800781. The reversal of 256161616800779 is 977008616161652.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-256161616800779 is a prime.
Together with 256161616800781, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (256161616800079) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128080808400389 + 128080808400390.
It is an arithmetic number, because the mean of its divisors is an integer number (128080808400390).
Almost surely, 2256161616800779 is an apocalyptic number.
256161616800779 is a deficient number, since it is larger than the sum of its proper divisors (1).
256161616800779 is an equidigital number, since it uses as much as digits as its factorization.
256161616800779 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45722880, while the sum is 65.
The spelling of 256161616800779 in words is "two hundred fifty-six trillion, one hundred sixty-one billion, six hundred sixteen million, eight hundred thousand, seven hundred seventy-nine".
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