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256507133064407 = 1394527918393833
BaseRepresentation
bin111010010100101010111000…
…100011000111010011010111
31020122012211202010122210200122
4322110222320203013103113
5232110103102031030112
62305313430011302155
7105013012610341601
oct7224527043072327
91218184663583618
10256507133064407
1174805078540135
1224928973a4a95b
13b018698c14b84
14474b023718171
151e9c514b1a872
hexe94ab88c74d7

256507133064407 has 4 divisors (see below), whose sum is σ = 256507165403520. Its totient is φ = 256507100725296.

The previous prime is 256507133064361. The next prime is 256507133064517. The reversal of 256507133064407 is 704460331705652.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 256507133064407 - 216 = 256507132998871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (256507133024407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4748363 + ... + 23142195.

It is an arithmetic number, because the mean of its divisors is an integer number (64126791350880).

Almost surely, 2256507133064407 is an apocalyptic number.

256507133064407 is a deficient number, since it is larger than the sum of its proper divisors (32339113).

256507133064407 is a wasteful number, since it uses less digits than its factorization.

256507133064407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32339112.

The product of its (nonzero) digits is 12700800, while the sum is 53.

The spelling of 256507133064407 in words is "two hundred fifty-six trillion, five hundred seven billion, one hundred thirty-three million, sixty-four thousand, four hundred seven".

Divisors: 1 13945279 18393833 256507133064407