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256507133064517 is a prime number
BaseRepresentation
bin111010010100101010111000…
…100011000111010101000101
31020122012211202010122210211201
4322110222320203013111011
5232110103102031031032
62305313430011302501
7105013012610342116
oct7224527043072505
91218184663583751
10256507133064517
1174805078540225
1224928973a4aa31
13b018698c14c3a
14474b02371820d
151e9c514b1a8e7
hexe94ab88c7545

256507133064517 has 2 divisors, whose sum is σ = 256507133064518. Its totient is φ = 256507133064516.

The previous prime is 256507133064361. The next prime is 256507133064661. The reversal of 256507133064517 is 715460331705652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 172803407811841 + 83703725252676 = 13145471^2 + 9148974^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-256507133064517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (256507133065517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128253566532258 + 128253566532259.

It is an arithmetic number, because the mean of its divisors is an integer number (128253566532259).

Almost surely, 2256507133064517 is an apocalyptic number.

It is an amenable number.

256507133064517 is a deficient number, since it is larger than the sum of its proper divisors (1).

256507133064517 is an equidigital number, since it uses as much as digits as its factorization.

256507133064517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15876000, while the sum is 55.

The spelling of 256507133064517 in words is "two hundred fifty-six trillion, five hundred seven billion, one hundred thirty-three million, sixty-four thousand, five hundred seventeen".