Base | Representation |
---|---|
bin | 1001100100010010… |
… | …1000011101010111 |
3 | 20121222101102210120 |
4 | 2121010220131113 |
5 | 20224420101333 |
6 | 1102455523023 |
7 | 120432505434 |
oct | 23104503527 |
9 | 6558342716 |
10 | 2568128343 |
11 | 10a8706920 |
12 | 5b8089473 |
13 | 31c094091 |
14 | 1a5106b8b |
15 | 1006d6db3 |
hex | 99128757 |
2568128343 has 8 divisors (see below), whose sum is σ = 3735459456. Its totient is φ = 1556441400.
The previous prime is 2568128327. The next prime is 2568128347. The reversal of 2568128343 is 3438218652.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2568128343 - 24 = 2568128327 is a prime.
It is a super-2 number, since 2×25681283432 = 13190566372239851298, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2568128295 and 2568128304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2568128347) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38911003 + ... + 38911068.
It is an arithmetic number, because the mean of its divisors is an integer number (466932432).
Almost surely, 22568128343 is an apocalyptic number.
2568128343 is a deficient number, since it is larger than the sum of its proper divisors (1167331113).
2568128343 is a wasteful number, since it uses less digits than its factorization.
2568128343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77822085.
The product of its digits is 276480, while the sum is 42.
The square root of 2568128343 is about 50676.7041450014. The cubic root of 2568128343 is about 1369.4270684068.
The spelling of 2568128343 in words is "two billion, five hundred sixty-eight million, one hundred twenty-eight thousand, three hundred forty-three".
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