Base | Representation |
---|---|
bin | 1110111101000000100… |
… | …0110010000011011111 |
3 | 220120002110022212000212 |
4 | 3233100020302003133 |
5 | 13202110112033232 |
6 | 314003240043035 |
7 | 24363045520304 |
oct | 3572010620337 |
9 | 816073285025 |
10 | 256895033567 |
11 | 99a48604aa7 |
12 | 4195576347b |
13 | 1b2c0702903 |
14 | c6104470ab |
15 | 6a382ebeb2 |
hex | 3bd02320df |
256895033567 has 2 divisors, whose sum is σ = 256895033568. Its totient is φ = 256895033566.
The previous prime is 256895033561. The next prime is 256895033569. The reversal of 256895033567 is 765330598652.
256895033567 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-256895033567 is a prime.
Together with 256895033569, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (256895033561) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128447516783 + 128447516784.
It is an arithmetic number, because the mean of its divisors is an integer number (128447516784).
Almost surely, 2256895033567 is an apocalyptic number.
256895033567 is a deficient number, since it is larger than the sum of its proper divisors (1).
256895033567 is an equidigital number, since it uses as much as digits as its factorization.
256895033567 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824000, while the sum is 59.
The spelling of 256895033567 in words is "two hundred fifty-six billion, eight hundred ninety-five million, thirty-three thousand, five hundred sixty-seven".
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