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257116127 is a prime number
BaseRepresentation
bin11110101001101…
…00011111011111
3122220210212000112
433110310133133
51011310204002
641302520235
76241310462
oct1724643737
9586725015
10257116127
11122154174
127213607b
1341364728
142620d2d9
151788c852
hexf5347df

257116127 has 2 divisors, whose sum is σ = 257116128. Its totient is φ = 257116126.

The previous prime is 257116121. The next prime is 257116129. The reversal of 257116127 is 721611752.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 257116127 - 220 = 256067551 is a prime.

It is a super-2 number, since 2×2571161272 = 132217405526960258, which contains 22 as substring.

Together with 257116129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 257116093 and 257116102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (257116121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128558063 + 128558064.

It is an arithmetic number, because the mean of its divisors is an integer number (128558064).

Almost surely, 2257116127 is an apocalyptic number.

257116127 is a deficient number, since it is larger than the sum of its proper divisors (1).

257116127 is an equidigital number, since it uses as much as digits as its factorization.

257116127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5880, while the sum is 32.

The square root of 257116127 is about 16034.8410344475. The cubic root of 257116127 is about 635.8818648176.

Adding to 257116127 its reverse (721611752), we get a palindrome (978727879).

The spelling of 257116127 in words is "two hundred fifty-seven million, one hundred sixteen thousand, one hundred twenty-seven".