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257148102997 is a prime number
BaseRepresentation
bin1110111101111100111…
…0001010100101010101
3220120202002112010000201
43233133032022211111
513203114403243442
6314044320140501
724402240545122
oct3573716124525
9816662463021
10257148102997
119a068444895
1241a06467731
131b330c7b436
14c635cc1749
156a5063a7b7
hex3bdf38a955

257148102997 has 2 divisors, whose sum is σ = 257148102998. Its totient is φ = 257148102996.

The previous prime is 257148102941. The next prime is 257148103021. The reversal of 257148102997 is 799201841752.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 256738809636 + 409293361 = 506694^2 + 20231^2 .

It is a cyclic number.

It is not a de Polignac number, because 257148102997 - 215 = 257148070229 is a prime.

It is a super-2 number, since 2×2571481029972 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (257148102097) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128574051498 + 128574051499.

It is an arithmetic number, because the mean of its divisors is an integer number (128574051499).

Almost surely, 2257148102997 is an apocalyptic number.

It is an amenable number.

257148102997 is a deficient number, since it is larger than the sum of its proper divisors (1).

257148102997 is an equidigital number, since it uses as much as digits as its factorization.

257148102997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 55.

The spelling of 257148102997 in words is "two hundred fifty-seven billion, one hundred forty-eight million, one hundred two thousand, nine hundred ninety-seven".