Base | Representation |
---|---|
bin | 111010100010000001000010… |
… | …001111111011000011000111 |
3 | 1020202110112001002002122102122 |
4 | 322202001002033323003013 |
5 | 232220114401424321320 |
6 | 2311255024435200155 |
7 | 105136201264042604 |
oct | 7242010217730307 |
9 | 1222415032078378 |
10 | 257424271323335 |
11 | 75029025141586 |
12 | 24a5666b74605b |
13 | b08400a21209c |
14 | 477d588ccd6ab |
15 | 1eb62e1a2ed25 |
hex | ea20423fb0c7 |
257424271323335 has 4 divisors (see below), whose sum is σ = 308909125588008. Its totient is φ = 205939417058664.
The previous prime is 257424271323257. The next prime is 257424271323361. The reversal of 257424271323335 is 533323172424752.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 257424271323335 - 224 = 257424254546119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25742427132329 + ... + 25742427132338.
It is an arithmetic number, because the mean of its divisors is an integer number (77227281397002).
Almost surely, 2257424271323335 is an apocalyptic number.
257424271323335 is a deficient number, since it is larger than the sum of its proper divisors (51484854264673).
257424271323335 is an equidigital number, since it uses as much as digits as its factorization.
257424271323335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51484854264672.
The product of its digits is 25401600, while the sum is 53.
The spelling of 257424271323335 in words is "two hundred fifty-seven trillion, four hundred twenty-four billion, two hundred seventy-one million, three hundred twenty-three thousand, three hundred thirty-five".
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