Base | Representation |
---|---|
bin | 11110110000111… |
… | …00101010111101 |
3 | 122222121011112222 |
4 | 33120130222331 |
5 | 1012031122013 |
6 | 41335135125 |
7 | 6252351212 |
oct | 1730345275 |
9 | 588534488 |
10 | 258067133 |
11 | 122743725 |
12 | 725144a5 |
13 | 4160855c |
14 | 263b9b09 |
15 | 179c9508 |
hex | f61cabd |
258067133 has 2 divisors, whose sum is σ = 258067134. Its totient is φ = 258067132.
The previous prime is 258067127. The next prime is 258067141. The reversal of 258067133 is 331760852.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 205692964 + 52374169 = 14342^2 + 7237^2 .
It is a cyclic number.
It is not a de Polignac number, because 258067133 - 212 = 258063037 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 258067093 and 258067102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (258067163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129033566 + 129033567.
It is an arithmetic number, because the mean of its divisors is an integer number (129033567).
Almost surely, 2258067133 is an apocalyptic number.
It is an amenable number.
258067133 is a deficient number, since it is larger than the sum of its proper divisors (1).
258067133 is an equidigital number, since it uses as much as digits as its factorization.
258067133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 35.
The square root of 258067133 is about 16064.4680272955. The cubic root of 258067133 is about 636.6648876839.
The spelling of 258067133 in words is "two hundred fifty-eight million, sixty-seven thousand, one hundred thirty-three".
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