2587134041 has 4 divisors (see below), whose sum is σ = 2589810432. Its totient is φ = 2584457652.

The previous prime is 2587134029. The next prime is 2587134079. The reversal of 2587134041 is 1404317852.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2587134041 - 2¹⁴ = 2587117657 is a prime.

It is a super-2 number, since 2×2587134041² = 13386525092201979362, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2587133992 and 2587134010.

It is not an unprimeable number, because it can be changed into a prime (2580134041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1336745 + ... + 1338678.

It is an arithmetic number, because the mean of its divisors is an integer number (647452608).

Almost surely, 2^2587134041 is an apocalyptic number.

It is an amenable number.

2587134041 is a deficient number, since it is larger than the sum of its proper divisors (2676391).

2587134041 is an equidigital number, since it uses as much as digits as its factorization.

2587134041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2676390.

The product of its (nonzero) digits is 26880, while the sum is 35.

The square root of 2587134041 is about 50863.8775655179. The cubic root of 2587134041 is about 1372.7969642411.

The spelling of 2587134041 in words is "two billion, five hundred eighty-seven million, one hundred thirty-four thousand, forty-one".