Base | Representation |
---|---|
bin | 11110110110000… |
… | …01000010010101 |
3 | 200000212101001210 |
4 | 33123001002111 |
5 | 1012214142443 |
6 | 41401412033 |
7 | 6261154053 |
oct | 1733010225 |
9 | 600771053 |
10 | 258740373 |
11 | 123063521 |
12 | 7279a019 |
13 | 417b2b18 |
14 | 265131d3 |
15 | 17aadc33 |
hex | f6c1095 |
258740373 has 4 divisors (see below), whose sum is σ = 344987168. Its totient is φ = 172493580.
The previous prime is 258740359. The next prime is 258740387. The reversal of 258740373 is 373047852.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (258740359) and next prime (258740387).
It is not a de Polignac number, because 258740373 - 29 = 258739861 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (258740393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43123393 + ... + 43123398.
It is an arithmetic number, because the mean of its divisors is an integer number (86246792).
Almost surely, 2258740373 is an apocalyptic number.
It is an amenable number.
258740373 is a deficient number, since it is larger than the sum of its proper divisors (86246795).
258740373 is an equidigital number, since it uses as much as digits as its factorization.
258740373 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86246794.
The product of its (nonzero) digits is 141120, while the sum is 39.
The square root of 258740373 is about 16085.4086985690. The cubic root of 258740373 is about 637.2180461731.
The spelling of 258740373 in words is "two hundred fifty-eight million, seven hundred forty thousand, three hundred seventy-three".
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