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2612214630017 is a prime number
BaseRepresentation
bin100110000000110100001…
…000000000011010000001
3100020201120201200101211122
4212000310020000122001
5320244303421130032
65320011305122025
7356504053666226
oct46006410003201
910221521611748
102612214630017
1191791a070733
12362321489315
1315c43b9637b5
149060906194d
1547e3a365012
hex26034200681

2612214630017 has 2 divisors, whose sum is σ = 2612214630018. Its totient is φ = 2612214630016.

The previous prime is 2612214629971. The next prime is 2612214630019. The reversal of 2612214630017 is 7100364122162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2386666573456 + 225548056561 = 1544884^2 + 474919^2 .

It is a cyclic number.

It is not a de Polignac number, because 2612214630017 - 214 = 2612214613633 is a prime.

Together with 2612214630019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2612214630019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1306107315008 + 1306107315009.

It is an arithmetic number, because the mean of its divisors is an integer number (1306107315009).

Almost surely, 22612214630017 is an apocalyptic number.

It is an amenable number.

2612214630017 is a deficient number, since it is larger than the sum of its proper divisors (1).

2612214630017 is an equidigital number, since it uses as much as digits as its factorization.

2612214630017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

Adding to 2612214630017 its reverse (7100364122162), we get a palindrome (9712578752179).

The spelling of 2612214630017 in words is "two trillion, six hundred twelve billion, two hundred fourteen million, six hundred thirty thousand, seventeen".