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26130399149 is a prime number
BaseRepresentation
bin11000010101011111…
…100011111110101101
32111110001221210221002
4120111133203332231
5412003340233044
620000521050045
71613351504501
oct302537437655
974401853832
1026130399149
1110099a246a8
125093026925
13260579ba5a
14139c55a301
15a2e06074e
hex6157e3fad

26130399149 has 2 divisors, whose sum is σ = 26130399150. Its totient is φ = 26130399148.

The previous prime is 26130399109. The next prime is 26130399283. The reversal of 26130399149 is 94199303162.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13607222500 + 12523176649 = 116650^2 + 111907^2 .

It is a cyclic number.

It is not a de Polignac number, because 26130399149 - 232 = 21835431853 is a prime.

It is a super-3 number, since 3×261303991493 (a number of 32 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (26130399109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13065199574 + 13065199575.

It is an arithmetic number, because the mean of its divisors is an integer number (13065199575).

Almost surely, 226130399149 is an apocalyptic number.

It is an amenable number.

26130399149 is a deficient number, since it is larger than the sum of its proper divisors (1).

26130399149 is an equidigital number, since it uses as much as digits as its factorization.

26130399149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 314928, while the sum is 47.

The spelling of 26130399149 in words is "twenty-six billion, one hundred thirty million, three hundred ninety-nine thousand, one hundred forty-nine".