Base | Representation |
---|---|
bin | 11000010101111100… |
… | …111001001110001111 |
3 | 2111110121102110111202 |
4 | 120111330321032033 |
5 | 412012322311320 |
6 | 20001353540115 |
7 | 1613504041112 |
oct | 302574711617 |
9 | 74417373452 |
10 | 26138088335 |
11 | 100a32a66a7 |
12 | 509571463b |
13 | 2607261878 |
14 | 139d59c579 |
15 | a2ea7db75 |
hex | 615f3938f |
26138088335 has 4 divisors (see below), whose sum is σ = 31365706008. Its totient is φ = 20910470664.
The previous prime is 26138088331. The next prime is 26138088337. The reversal of 26138088335 is 53388083162.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53388083162 = 2 ⋅26694041581.
It is a cyclic number.
It is not a de Polignac number, because 26138088335 - 22 = 26138088331 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 26138088335.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (26138088331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2613808829 + ... + 2613808838.
It is an arithmetic number, because the mean of its divisors is an integer number (7841426502).
Almost surely, 226138088335 is an apocalyptic number.
26138088335 is a deficient number, since it is larger than the sum of its proper divisors (5227617673).
26138088335 is an equidigital number, since it uses as much as digits as its factorization.
26138088335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5227617672.
The product of its (nonzero) digits is 829440, while the sum is 47.
The spelling of 26138088335 in words is "twenty-six billion, one hundred thirty-eight million, eighty-eight thousand, three hundred thirty-five".
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