26290505441 has 2 divisors, whose sum is σ = 26290505442. Its totient is φ = 26290505440.

The previous prime is 26290505431. The next prime is 26290505443. The reversal of 26290505441 is 14450509262.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25194895441 + 1095610000 = 158729^2 + 33100^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-26290505441 is a prime.

Together with 26290505443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 26290505395 and 26290505404.

It is not a weakly prime, because it can be changed into another prime (26290505443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13145252720 + 13145252721.

It is an arithmetic number, because the mean of its divisors is an integer number (13145252721).

Almost surely, 2^26290505441 is an apocalyptic number.

It is an amenable number.

26290505441 is a deficient number, since it is larger than the sum of its proper divisors (1).

26290505441 is an equidigital number, since it uses as much as digits as its factorization.

26290505441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 38.

The spelling of 26290505441 in words is "twenty-six billion, two hundred ninety million, five hundred five thousand, four hundred forty-one".