264011419813 has 2 divisors, whose sum is σ = 264011419814. Its totient is φ = 264011419812.

The previous prime is 264011419799. The next prime is 264011419873. The reversal of 264011419813 is 318914110462.

It is a happy number.

264011419813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 263767497889 + 243921924 = 513583^2 + 15618^2 .

It is a cyclic number.

It is not a de Polignac number, because 264011419813 - 2¹⁷ = 264011288741 is a prime.

It is a super-2 number, since 2×264011419813² (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (264011419873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132005709906 + 132005709907.

It is an arithmetic number, because the mean of its divisors is an integer number (132005709907).

Almost surely, 2^264011419813 is an apocalyptic number.

It is an amenable number.

264011419813 is a deficient number, since it is larger than the sum of its proper divisors (1).

264011419813 is an equidigital number, since it uses as much as digits as its factorization.

264011419813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 40.

The spelling of 264011419813 in words is "two hundred sixty-four billion, eleven million, four hundred nineteen thousand, eight hundred thirteen".