Search a number
-
+
264037497137 = 1371927281001
BaseRepresentation
bin1111010111100111011…
…1000111100100110001
3221020112020010121002122
43311321313013210301
513311222044402022
6321144103524025
725035044460251
oct3657167074461
9836466117078
10264037497137
11a1a83313657
1243209759615
131bb8b39930b
14cacac89961
156d053a7742
hex3d79dc7931

264037497137 has 4 divisors (see below), whose sum is σ = 265964778276. Its totient is φ = 262110216000.

The previous prime is 264037497083. The next prime is 264037497167. The reversal of 264037497137 is 731794730462.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 193810377121 + 70227120016 = 440239^2 + 265004^2 .

It is a cyclic number.

It is not a de Polignac number, because 264037497137 - 210 = 264037496113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (264037497167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 963640364 + ... + 963640637.

It is an arithmetic number, because the mean of its divisors is an integer number (66491194569).

Almost surely, 2264037497137 is an apocalyptic number.

It is an amenable number.

264037497137 is a deficient number, since it is larger than the sum of its proper divisors (1927281139).

264037497137 is a wasteful number, since it uses less digits than its factorization.

264037497137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1927281138.

The product of its (nonzero) digits is 5334336, while the sum is 53.

The spelling of 264037497137 in words is "two hundred sixty-four billion, thirty-seven million, four hundred ninety-seven thousand, one hundred thirty-seven".

Divisors: 1 137 1927281001 264037497137