Base | Representation |
---|---|
bin | 1001110101100001… |
… | …1011110110110111 |
3 | 20211000102122221002 |
4 | 2131120123312313 |
5 | 20401422202341 |
6 | 1114001313515 |
7 | 122301162122 |
oct | 23530336667 |
9 | 6730378832 |
10 | 2640428471 |
11 | 11354a8a9a |
12 | 61833589b |
13 | 331059815 |
14 | 1b09673b9 |
15 | 106c1929b |
hex | 9d61bdb7 |
2640428471 has 2 divisors, whose sum is σ = 2640428472. Its totient is φ = 2640428470.
The previous prime is 2640428429. The next prime is 2640428473. The reversal of 2640428471 is 1748240462.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2640428471 - 230 = 1566686647 is a prime.
It is a super-3 number, since 3×26404284713 (a number of 29 digits) contains 333 as substring.
Together with 2640428473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2640428473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1320214235 + 1320214236.
It is an arithmetic number, because the mean of its divisors is an integer number (1320214236).
Almost surely, 22640428471 is an apocalyptic number.
2640428471 is a deficient number, since it is larger than the sum of its proper divisors (1).
2640428471 is an equidigital number, since it uses as much as digits as its factorization.
2640428471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 38.
The square root of 2640428471 is about 51385.0996982588. The cubic root of 2640428471 is about 1382.1594125624.
The spelling of 2640428471 in words is "two billion, six hundred forty million, four hundred twenty-eight thousand, four hundred seventy-one".
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