Base | Representation |
---|---|
bin | 100110011011101000001… |
… | …000000000000011110111 |
3 | 100100110220010120202102200 |
4 | 212123220020000003313 |
5 | 321232234102100010 |
6 | 5341132144235543 |
7 | 361543356264243 |
oct | 46335010000367 |
9 | 10313803522380 |
10 | 2641004331255 |
11 | 929053104354 |
12 | 367a1700bbb3 |
13 | 162079369884 |
14 | 91b7a859423 |
15 | 48a72abbcc0 |
hex | 266e82000f7 |
2641004331255 has 96 divisors (see below), whose sum is σ = 4751035680768. Its totient is φ = 1355716051200.
The previous prime is 2641004331209. The next prime is 2641004331281. The reversal of 2641004331255 is 5521334001462.
2641004331255 is a `hidden beast` number, since 2 + 64 + 10 + 0 + 4 + 331 + 255 = 666.
It is not a de Polignac number, because 2641004331255 - 28 = 2641004330999 is a prime.
It is a super-3 number, since 3×26410043312553 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 726147297 + ... + 726150933.
It is an arithmetic number, because the mean of its divisors is an integer number (49489955008).
Almost surely, 22641004331255 is an apocalyptic number.
2641004331255 is a deficient number, since it is larger than the sum of its proper divisors (2110031349513).
2641004331255 is a wasteful number, since it uses less digits than its factorization.
2641004331255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6357 (or 6354 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
The spelling of 2641004331255 in words is "two trillion, six hundred forty-one billion, four million, three hundred thirty-one thousand, two hundred fifty-five".
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