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2641025113 is a prime number
BaseRepresentation
bin1001110101101010…
…1101100001011001
320211001112222100221
42131122231201121
520402100300423
61114022200041
7122306225446
oct23532554131
96731488327
102641025113
111135876291
12618583021
1333120826c
141b0a809cd
15106cd5e5d
hex9d6ad859

2641025113 has 2 divisors, whose sum is σ = 2641025114. Its totient is φ = 2641025112.

The previous prime is 2641025069. The next prime is 2641025131. The reversal of 2641025113 is 3115201462.

It is a happy number.

Together with next prime (2641025131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1586269584 + 1054755529 = 39828^2 + 32477^2 .

It is a cyclic number.

It is not a de Polignac number, because 2641025113 - 29 = 2641024601 is a prime.

It is not a weakly prime, because it can be changed into another prime (2641005113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1320512556 + 1320512557.

It is an arithmetic number, because the mean of its divisors is an integer number (1320512557).

Almost surely, 22641025113 is an apocalyptic number.

It is an amenable number.

2641025113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2641025113 is an equidigital number, since it uses as much as digits as its factorization.

2641025113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 2641025113 is about 51390.9049638163. The cubic root of 2641025113 is about 1382.2635108503.

Adding to 2641025113 its reverse (3115201462), we get a palindrome (5756226575).

The spelling of 2641025113 in words is "two billion, six hundred forty-one million, twenty-five thousand, one hundred thirteen".