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26430643712129 is a prime number
BaseRepresentation
bin1100000001001110111010…
…01000010011000010000001
310110120202010000010021221212
412000213131020103002001
511431014424242242004
6132114023050255505
75365356663500516
oct600473510230201
9113522100107855
1026430643712129
11847019a36a308
122b6a529127595
131199525808bb7
1467536dd3d30d
1530c7c5ae596e
hex1809dd213081

26430643712129 has 2 divisors, whose sum is σ = 26430643712130. Its totient is φ = 26430643712128.

The previous prime is 26430643712023. The next prime is 26430643712131. The reversal of 26430643712129 is 92121734603462.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15152646169600 + 11277997542529 = 3892640^2 + 3358273^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-26430643712129 is a prime.

Together with 26430643712131, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (26430643712929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13215321856064 + 13215321856065.

It is an arithmetic number, because the mean of its divisors is an integer number (13215321856065).

Almost surely, 226430643712129 is an apocalyptic number.

It is an amenable number.

26430643712129 is a deficient number, since it is larger than the sum of its proper divisors (1).

26430643712129 is an equidigital number, since it uses as much as digits as its factorization.

26430643712129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 50.

The spelling of 26430643712129 in words is "twenty-six trillion, four hundred thirty billion, six hundred forty-three million, seven hundred twelve thousand, one hundred twenty-nine".