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26430643712131 is a prime number
BaseRepresentation
bin1100000001001110111010…
…01000010011000010000011
310110120202010000010021221221
412000213131020103002003
511431014424242242011
6132114023050255511
75365356663500521
oct600473510230203
9113522100107857
1026430643712131
11847019a36a30a
122b6a529127597
131199525808bb9
1467536dd3d311
1530c7c5ae5971
hex1809dd213083

26430643712131 has 2 divisors, whose sum is σ = 26430643712132. Its totient is φ = 26430643712130.

The previous prime is 26430643712129. The next prime is 26430643712147. The reversal of 26430643712131 is 13121734603462.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 26430643712131 - 21 = 26430643712129 is a prime.

It is a super-2 number, since 2×264306437121312 (a number of 28 digits) contains 22 as substring.

Together with 26430643712129, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (26430643712171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13215321856065 + 13215321856066.

It is an arithmetic number, because the mean of its divisors is an integer number (13215321856066).

Almost surely, 226430643712131 is an apocalyptic number.

26430643712131 is a deficient number, since it is larger than the sum of its proper divisors (1).

26430643712131 is an equidigital number, since it uses as much as digits as its factorization.

26430643712131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 435456, while the sum is 43.

The spelling of 26430643712131 in words is "twenty-six trillion, four hundred thirty billion, six hundred forty-three million, seven hundred twelve thousand, one hundred thirty-one".