264334614342431 has 2 divisors, whose sum is σ = 264334614342432. Its totient is φ = 264334614342430.

The previous prime is 264334614342353. The next prime is 264334614342433. The reversal of 264334614342431 is 134243416433462.

264334614342431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 264334614342431 - 2¹⁴ = 264334614326047 is a prime.

It is a super-2 number, since 2×264334614342431² (a number of 30 digits) contains 22 as substring.

Together with 264334614342433, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 264334614342431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (264334614342433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132167307171215 + 132167307171216.

It is an arithmetic number, because the mean of its divisors is an integer number (132167307171216).

Almost surely, 2^{264334614342431} is an apocalyptic number.

264334614342431 is a deficient number, since it is larger than the sum of its proper divisors (1).

264334614342431 is an equidigital number, since it uses as much as digits as its factorization.

264334614342431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11943936, while the sum is 50.

The spelling of 264334614342431 in words is "two hundred sixty-four trillion, three hundred thirty-four billion, six hundred fourteen million, three hundred forty-two thousand, four hundred thirty-one".