Base | Representation |
---|---|
bin | 111100000111100010101110… |
… | …011011101010111110010110 |
3 | 1021200011111111012000122122210 |
4 | 330013202232123222332112 |
5 | 234123421434441400004 |
6 | 2334200110010334250 |
7 | 106456231031551506 |
oct | 7407425633527626 |
9 | 1250144435018583 |
10 | 264401113231254 |
11 | 7727897855054a |
12 | 257a2859a2a386 |
13 | b46bbc1aa833c |
14 | 4941121643a06 |
15 | 2087a2e0e2089 |
hex | f078ae6eaf96 |
264401113231254 has 64 divisors (see below), whose sum is σ = 564279390144000. Its totient is φ = 82303002643968.
The previous prime is 264401113231207. The next prime is 264401113231301. The reversal of 264401113231254 is 452132311104462.
It is an interprime number because it is at equal distance from previous prime (264401113231207) and next prime (264401113231301).
It is a super-3 number, since 3×2644011132312543 (a number of 44 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4501729 + ... + 23432195.
It is an arithmetic number, because the mean of its divisors is an integer number (8816865471000).
Almost surely, 2264401113231254 is an apocalyptic number.
264401113231254 is an abundant number, since it is smaller than the sum of its proper divisors (299878276912746).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
264401113231254 is a wasteful number, since it uses less digits than its factorization.
264401113231254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18931557.
The product of its (nonzero) digits is 138240, while the sum is 39.
The spelling of 264401113231254 in words is "two hundred sixty-four trillion, four hundred one billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred fifty-four".
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