2644050433 has 4 divisors (see below), whose sum is σ = 2646719488. Its totient is φ = 2641381380.

The previous prime is 2644050397. The next prime is 2644050449. The reversal of 2644050433 is 3340504462.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2644050433 - 2⁹ = 2644049921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2644050395 and 2644050404.

It is not an unprimeable number, because it can be changed into a prime (2644050463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1333041 + ... + 1335022.

It is an arithmetic number, because the mean of its divisors is an integer number (661679872).

Almost surely, 2^2644050433 is an apocalyptic number.

It is an amenable number.

2644050433 is a deficient number, since it is larger than the sum of its proper divisors (2669055).

2644050433 is an equidigital number, since it uses as much as digits as its factorization.

2644050433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2669054.

The product of its (nonzero) digits is 34560, while the sum is 31.

The square root of 2644050433 is about 51420.3309304792. The cubic root of 2644050433 is about 1382.7911082189.

Adding to 2644050433 its reverse (3340504462), we get a palindrome (5984554895).

The spelling of 2644050433 in words is "two billion, six hundred forty-four million, fifty thousand, four hundred thirty-three".