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2655313514039 is a prime number
BaseRepresentation
bin100110101000111101000…
…001001100111000110111
3100101211211100211120001102
4212220331001030320313
5322001040224422124
65351500103520315
7362561100316304
oct46507501147067
910354740746042
102655313514039
1193412628914a
1236a74b15909b
13163519a40134
14927370160ab
154910de24aae
hex26a3d04ce37

2655313514039 has 2 divisors, whose sum is σ = 2655313514040. Its totient is φ = 2655313514038.

The previous prime is 2655313513999. The next prime is 2655313514041. The reversal of 2655313514039 is 9304153135562.

2655313514039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2655313514039 - 228 = 2655045078583 is a prime.

It is a Sophie Germain prime.

Together with 2655313514041, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2655313513984 and 2655313514002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2655313814039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1327656757019 + 1327656757020.

It is an arithmetic number, because the mean of its divisors is an integer number (1327656757020).

Almost surely, 22655313514039 is an apocalyptic number.

2655313514039 is a deficient number, since it is larger than the sum of its proper divisors (1).

2655313514039 is an equidigital number, since it uses as much as digits as its factorization.

2655313514039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458000, while the sum is 47.

The spelling of 2655313514039 in words is "two trillion, six hundred fifty-five billion, three hundred thirteen million, five hundred fourteen thousand, thirty-nine".