Base | Representation |
---|---|
bin | 11111101110000… |
… | …01010001000001 |
3 | 200112200022222122 |
4 | 33313001101001 |
5 | 1021104100340 |
6 | 42223014025 |
7 | 6410440235 |
oct | 1767012101 |
9 | 615608878 |
10 | 266081345 |
11 | 127217942 |
12 | 7513a315 |
13 | 431832aa |
14 | 274a45c5 |
15 | 1855ddb5 |
hex | fdc1441 |
266081345 has 4 divisors (see below), whose sum is σ = 319297620. Its totient is φ = 212865072.
The previous prime is 266081323. The next prime is 266081371. The reversal of 266081345 is 543180662.
It is a Cunningham number, because it is equal to 163122+1.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543180662 = 2 ⋅271590331.
It can be written as a sum of positive squares in 2 ways, for example, as 95804944 + 170276401 = 9788^2 + 13049^2 .
It is a cyclic number.
It is not a de Polignac number, because 266081345 - 224 = 249304129 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26608130 + ... + 26608139.
It is an arithmetic number, because the mean of its divisors is an integer number (79824405).
Almost surely, 2266081345 is an apocalyptic number.
It is an amenable number.
266081345 is a deficient number, since it is larger than the sum of its proper divisors (53216275).
266081345 is an equidigital number, since it uses as much as digits as its factorization.
266081345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53216274.
The product of its (nonzero) digits is 34560, while the sum is 35.
The square root of 266081345 is about 16312.0000306523. Note that the first 4 decimals coincide. The cubic root of 266081345 is about 643.1883098760.
The spelling of 266081345 in words is "two hundred sixty-six million, eighty-one thousand, three hundred forty-five".
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