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2741135244493 is a prime number
BaseRepresentation
bin100111111000111000011…
…001000111110011001101
3100201001100102120011212211
4213320320121013303031
5324402321110310433
65455132105230421
7402016613066062
oct47707031076315
910631312504784
102741135244493
11967566425508
12383300792411
1316b646024669
1496959036c69
154b4835658cd
hex27e38647ccd

2741135244493 has 2 divisors, whose sum is σ = 2741135244494. Its totient is φ = 2741135244492.

The previous prime is 2741135244439. The next prime is 2741135244511. The reversal of 2741135244493 is 3944425311472.

Together with previous prime (2741135244439) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2333552594409 + 407582650084 = 1527597^2 + 638422^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2741135244493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2741135244413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1370567622246 + 1370567622247.

It is an arithmetic number, because the mean of its divisors is an integer number (1370567622247).

Almost surely, 22741135244493 is an apocalyptic number.

It is an amenable number.

2741135244493 is a deficient number, since it is larger than the sum of its proper divisors (1).

2741135244493 is an equidigital number, since it uses as much as digits as its factorization.

2741135244493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2903040, while the sum is 49.

The spelling of 2741135244493 in words is "two trillion, seven hundred forty-one billion, one hundred thirty-five million, two hundred forty-four thousand, four hundred ninety-three".