Base | Representation |
---|---|
bin | 1000000000010110110… |
… | …01011010010000011111 |
3 | 222022000001001222021112 |
4 | 10000023121122100133 |
5 | 14001320143224341 |
6 | 330210501452235 |
7 | 25605316630541 |
oct | 4001331322037 |
9 | 868001058245 |
10 | 275069117471 |
11 | a6724389255 |
12 | 4538811107b |
13 | 1cc28a15305 |
14 | d45602b691 |
15 | 724dae0aeb |
hex | 400b65a41f |
275069117471 has 2 divisors, whose sum is σ = 275069117472. Its totient is φ = 275069117470.
The previous prime is 275069117459. The next prime is 275069117473. The reversal of 275069117471 is 174711960572.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 275069117471 - 210 = 275069116447 is a prime.
It is a super-3 number, since 3×2750691174713 (a number of 35 digits) contains 333 as substring.
Together with 275069117473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (275069117473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 137534558735 + 137534558736.
It is an arithmetic number, because the mean of its divisors is an integer number (137534558736).
Almost surely, 2275069117471 is an apocalyptic number.
275069117471 is a deficient number, since it is larger than the sum of its proper divisors (1).
275069117471 is an equidigital number, since it uses as much as digits as its factorization.
275069117471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 740880, while the sum is 50.
The spelling of 275069117471 in words is "two hundred seventy-five billion, sixty-nine million, one hundred seventeen thousand, four hundred seventy-one".
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