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2813115557407 = 12241229810927
BaseRepresentation
bin101000111011111010110…
…000001110011000011111
3100221221010212012221101011
4220323322300032120133
5332042230040314112
65552154421200051
7410145424463551
oct50737260163037
910857125187334
102813115557407
11995043437a21
1239524a860027
131753778124ac
149a226a614d1
154d29794aaa7
hex28efac0e61f

2813115557407 has 4 divisors (see below), whose sum is σ = 2813345380576. Its totient is φ = 2812885734240.

The previous prime is 2813115557401. The next prime is 2813115557423. The reversal of 2813115557407 is 7047555113182.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2813115557407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2813115557401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114893223 + ... + 114917704.

It is an arithmetic number, because the mean of its divisors is an integer number (703336345144).

Almost surely, 22813115557407 is an apocalyptic number.

2813115557407 is a deficient number, since it is larger than the sum of its proper divisors (229823169).

2813115557407 is a wasteful number, since it uses less digits than its factorization.

2813115557407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229823168.

The product of its (nonzero) digits is 1176000, while the sum is 49.

The spelling of 2813115557407 in words is "two trillion, eight hundred thirteen billion, one hundred fifteen million, five hundred fifty-seven thousand, four hundred seven".

Divisors: 1 12241 229810927 2813115557407