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28373506491623 is a prime number
BaseRepresentation
bin1100111001110001110001…
…10001101000010011100111
310201110110222110012121100212
412130320320301220103213
512204332420130212443
6140202335310330035
75655626640601016
oct634707061502347
9121413873177325
1028373506491623
11904a15579a6a7
123222b85ab991b
1312aa7c1751447
147013dc222a7d
153430d785b618
hex19ce38c684e7

28373506491623 has 2 divisors, whose sum is σ = 28373506491624. Its totient is φ = 28373506491622.

The previous prime is 28373506491593. The next prime is 28373506491643. The reversal of 28373506491623 is 32619460537382.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 28373506491623 - 210 = 28373506490599 is a prime.

It is a super-3 number, since 3×283735064916233 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (28373506491643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14186753245811 + 14186753245812.

It is an arithmetic number, because the mean of its divisors is an integer number (14186753245812).

It is a 2-persistent number, because it is pandigital, and so is 2⋅28373506491623 = 56747012983246, but 3⋅28373506491623 = 85120519474869 is not.

Almost surely, 228373506491623 is an apocalyptic number.

28373506491623 is a deficient number, since it is larger than the sum of its proper divisors (1).

28373506491623 is an equidigital number, since it uses as much as digits as its factorization.

28373506491623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 39191040, while the sum is 59.

The spelling of 28373506491623 in words is "twenty-eight trillion, three hundred seventy-three billion, five hundred six million, four hundred ninety-one thousand, six hundred twenty-three".