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28477063981 is a prime number
BaseRepresentation
bin11010100001010111…
…011000001100101101
32201111121121201220101
4122201113120030231
5431310112021411
621025430151101
72025455023102
oct324127301455
981447551811
1028477063981
1111093618723
125628ab2491
1328baa02222
141542094aa9
15b1a09d8c1
hex6a15d832d

28477063981 has 2 divisors, whose sum is σ = 28477063982. Its totient is φ = 28477063980.

The previous prime is 28477063933. The next prime is 28477063999. The reversal of 28477063981 is 18936077482.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23902706025 + 4574357956 = 154605^2 + 67634^2 .

It is a cyclic number.

It is not a de Polignac number, because 28477063981 - 29 = 28477063469 is a prime.

It is a super-2 number, since 2×284770639812 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (28477060981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14238531990 + 14238531991.

It is an arithmetic number, because the mean of its divisors is an integer number (14238531991).

Almost surely, 228477063981 is an apocalyptic number.

It is an amenable number.

28477063981 is a deficient number, since it is larger than the sum of its proper divisors (1).

28477063981 is an equidigital number, since it uses as much as digits as its factorization.

28477063981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4064256, while the sum is 55.

The spelling of 28477063981 in words is "twenty-eight billion, four hundred seventy-seven million, sixty-three thousand, nine hundred eighty-one".