Base | Representation |
---|---|
bin | 1000010011000000110… |
… | …00111110010011000111 |
3 | 1000020212001201120101011 |
4 | 10021200120332103013 |
5 | 14132323230012103 |
6 | 334544412543051 |
7 | 26411446345063 |
oct | 4114030762307 |
9 | 1006761646334 |
10 | 285085000903 |
11 | aa9a406176a |
12 | 47302481a87 |
13 | 20b63aa4261 |
14 | db26326aa3 |
15 | 7638089d6d |
hex | 426063e4c7 |
285085000903 has 2 divisors, whose sum is σ = 285085000904. Its totient is φ = 285085000902.
The previous prime is 285085000841. The next prime is 285085000919. The reversal of 285085000903 is 309000580582.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 285085000903 - 233 = 276495066311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (285085007903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 142542500451 + 142542500452.
It is an arithmetic number, because the mean of its divisors is an integer number (142542500452).
Almost surely, 2285085000903 is an apocalyptic number.
285085000903 is a deficient number, since it is larger than the sum of its proper divisors (1).
285085000903 is an equidigital number, since it uses as much as digits as its factorization.
285085000903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 285085000903 in words is "two hundred eighty-five billion, eighty-five million, nine hundred three", and thus it is an aban number.
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