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28625113 = 112602283
BaseRepresentation
bin110110100110…
…0100011011001
31222212022021101
41231030203121
524312000423
62501311401
7465211066
oct155144331
958768241
1028625113
1115181520
129705561
135c1324a
143b31c6d
1527a67ad
hex1b4c8d9

28625113 has 4 divisors (see below), whose sum is σ = 31227408. Its totient is φ = 26022820.

The previous prime is 28625111. The next prime is 28625119. The reversal of 28625113 is 31152682.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 28625113 - 21 = 28625111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (28625111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1301131 + ... + 1301152.

It is an arithmetic number, because the mean of its divisors is an integer number (7806852).

Almost surely, 228625113 is an apocalyptic number.

It is an amenable number.

28625113 is a deficient number, since it is larger than the sum of its proper divisors (2602295).

28625113 is a wasteful number, since it uses less digits than its factorization.

28625113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2602294.

The product of its digits is 2880, while the sum is 28.

The square root of 28625113 is about 5350.2442000342. The cubic root of 28625113 is about 305.9020611569.

Adding to 28625113 its reverse (31152682), we get a palindrome (59777795).

The spelling of 28625113 in words is "twenty-eight million, six hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 11 2602283 28625113