Base | Representation |
---|---|
bin | 101010011001110001001… |
… | …110110101111100001010 |
3 | 101022120020211111012211201 |
4 | 222121301032311330022 |
5 | 340220120202334200 |
6 | 10110342122414414 |
7 | 420343564310221 |
oct | 52316116657412 |
9 | 11276224435751 |
10 | 2913887543050 |
11 | a2385560a290 |
12 | 3b089306140a |
13 | 181a17246873 |
14 | a1066437cb8 |
15 | 50be4826c6a |
hex | 2a6713b5f0a |
2913887543050 has 48 divisors (see below), whose sum is σ = 5920192413792. Its totient is φ = 1058224558400.
The previous prime is 2913887542999. The next prime is 2913887543071. The reversal of 2913887543050 is 503457883192.
It is a super-2 number, since 2×29138875430502 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (55).
It is a junction number, because it is equal to n+sod(n) for n = 2913887542982 and 2913887543000.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3001744 + ... + 3852043.
It is an arithmetic number, because the mean of its divisors is an integer number (123337341954).
Almost surely, 22913887543050 is an apocalyptic number.
2913887543050 is an abundant number, since it is smaller than the sum of its proper divisors (3006304870742).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2913887543050 is a wasteful number, since it uses less digits than its factorization.
2913887543050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6854583 (or 6854578 counting only the distinct ones).
The product of its (nonzero) digits is 7257600, while the sum is 55.
The spelling of 2913887543050 in words is "two trillion, nine hundred thirteen billion, eight hundred eighty-seven million, five hundred forty-three thousand, fifty".
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